All categories

2 years ago

For this graph mark the statements that are true. HELP ME PLEASE!

Mathematics

1 answer:

lisov135 [29]2 years ago

5 0

Answer:

c i believe

Step-by-step explanation:

You might be interested in

Is this correct?????

fomenos

Answer: $\bold{x^8}$

<u>Step-by-step explanation:</u>

$x^3\cdot x^5\quad =x^{3+5}\quad =\large\boxed{x^8}$

7 0

2 years ago

Solve w^2 + 7w - 18 = 0<br><br>with the steps pls

Bess [88]

Answer:

w=2 w = -9

Step-by-step explanation:

w^2 + 7w - 18 = 0

We can factor this equation

What 2 numbers multiply to -18 and add to 7

9*-2 = -18

9+-2 = 7

(w-2) (w+9) = 0

Using the zero product property

w-2 = 0 w+9 =0

w=2 w = -9

4 0

2 years ago

Read 2 more answers

Y=4x+8 y=-x-7 solve by substitution

nikklg [1K]

Step-by-step explanation:

Alrighty! here you go image.

7 0

2 years ago

Read 2 more answers

First 8 is added to me , then j am multiplied by 6.then 40 is subtracted from me .Finally I am divided by 10. The result is 11.

alexdok [17]

11x10=110
110+40=150
150/6=25
25-8=17
17 is the number.

4 0

2 years ago

Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21

yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to $-4x+7y=21$ .

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

$-4x+7y=21$

Slope of this line is

$m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{-4}{7}$

$m_1=\dfrac{4}{7}$

Product of slope of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{4}{7}\times m_2=-1$

$m_2=-\dfrac{7}{4}$

Now, slope of required line is $-\dfrac{7}{4}$ and it passes through (1,-2). So, the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-2)=-\dfrac{7}{4}(x-1)$

$4(y+2)=-7(x-1)$

$4y+8=-7x+7$

$4y+7x=7-8$

$7x+4y=-1$

Therefore, the equation of required line is $7x+4y=-1$ .

7 0

2 years ago