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frez [133]
3 years ago
8

2x/x2-25=10/x2-25 - 4/x+5

Mathematics
1 answer:
spayn [35]3 years ago
7 0
First of all you need push the restriction for what x value the denominator result 0 bc. than this fraction will be undefined 
- so x^2 -25 = 0
(x-5)(x+5)=0
x-5=0 =>x=5
and 
x+5=0 =>x=-5
so this mean that x not can being equal +/- 5 

rewrite :
x^2 -25 = (x-5)(x+5)

   2x                       10                 4
------------- = ------------------ - -----------
(x-5)(x+5)       (x-5)(x+5)          x +5

    2x = 10 -4(x-5)
2x = 10 -4x +20

6x = 30

x = 30/6

x = 5 what is restriction for x 

hope helped 


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PLEASE HELP
NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base

H is the height of the pyramid

we have

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substitute and solve for B

40=\frac{1}{3}B(6)

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step 2

Find the volume of the rectangular prism with the same base area and height

we know that

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V=BH

we have

B=20\ units^{2}

H=6\ units

substitute

V=(20)(6)=120\ units^{3}

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

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4 years ago
4. Amazon executives believe that at least 70% of customers would return a product 2 days after it arrives at their home. A samp
inysia [295]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
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  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • Sample of 500 customers, hence n = 500.
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The <u>mean and the standard error</u> are given by:

\mu = p = 0.7

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.7(0.3)}{500}} = 0.0205

The probability is the <u>p-value of Z when X = 0.68</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

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Z = -0.98

Z = -0.98 has a p-value of 0.1635.

0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

A similar problem is given at brainly.com/question/25735688

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Therefore at x = -3 , f'(x) = -10.

Hence the function is increasing in the interval of (-∞, -3)

Again f'(x) = 2x² + 12x + 8 , so after first differentiation we get :

That the function is also increasing in the interval (-1,∞)

Now for the interval (-4,-2), we can say that the graph of the function is positive as the y value increases and then decreases but all y values are positive as illustrated in the graph.

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