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finlep [7]
3 years ago
10

There are between 24 and 40 students in the class

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer:

33 Students

Step-by-step explanation:

4+7=11 so the number of students in the class must be a multiple of 11. The only multiple of 11 between 24 and 40 is 33.

LiRa [457]3 years ago
6 0

Answer:

33

Step-by-step explanation:

Let's take the constant of proportionality to be X

4x+7x=between 24 to 40

11x= 24 to 40

X should be a natural number therefore the number of students should be multiple of 11

Only multiple of 11 between 24 and 40 is 33

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Find the reference angle for 105 degree angle.
m_a_m_a [10]

Answer:

75° degree angle

Step-by-step explanation:

Since the angle 105° is in the second quadrant, subtract 105° from 180° .

180-105=75

6 0
3 years ago
Read 2 more answers
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
2.) A cubic function that has 3 zeros: 2, -5, and 7.
stiv31 [10]

Answer:

65

Step-by-step explanation:

8 0
3 years ago
Warm up help plz and thx
galina1969 [7]

Answer:

D. for the first one and B. for the second one i think

4 0
3 years ago
The sum of three numbers 13. The sum of twice the first number, five times the second number, and six times the third number is
Kruka [31]

Answer:

The three numbers are 56/5, -39/5 and 78/5.

Step-by-step explanation:

EQUATION 1:

First number: x

Second number: y

Third number: z

x + y + z = 19

EQUATION 2:

Sum of following is 77

Twice the first number: 2x

5 times the second number: 5y

6 times the third number: 6z

So, 2x + 5y + 6z = 77

EQUATION 3:

Difference between first and second number is 19.

x - y = 19

Equation 1: x + y + z = 19

Equation 2: 2x + 5y + 6z = 77

Equation 3: x - y = 19

1. Find x in terms of y

x - y = 19

x = 19 + y

2. Find y in terms of z by putting the value of x in first and second equation

  x + y + z = 19

  (19 + y)+ y + z = 19

  2y + z = 19 - 19

  2y + z = 0

  y = -z/2

and

2(19+y)+5y+6z=77

now putting the value of y in this equation

2(19-z/2)+5(-z/2)+6z=77

38 - z -5z/2 +6z = 77

5z/2 + 38 = 77

5z/2 = 39

z = 78/5

Now, y = -z/2

y = (-78/5)/2

y = -39/5

and  x = 19 + y

x = 19 - 39/5

x = 56/5

Therefore, the three numbers are 56/5, -39/5 and 78/5.

Keyword: Sum

Learn more about sum at

brainly.com/question/10666510

brainly.com/question/4034547

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
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