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olga55 [171]
3 years ago
9

Write one problem statement for each subject area that stactistics can solve

Mathematics
1 answer:
Scilla [17]3 years ago
7 0

Answer:

look in explanation

Step-by-step explanation:

what is the probability of the ball hitting u in dodge ball in pe

what is the ratio of your computer to everyone else's in comp science

how much of your essay did you finish (in a fraction)

how many people are there in psychology class for every notebook?

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On a map,1 in. represents 12 mi. Two cities are 6 1/2 in. on a map. How far apart are the actual cities? A. 78 mi B. 72 1/2 mi C
Dovator [93]
1 inch= 12 miles


Multiply 6 1/2 inches by total number of miles per 1 inch (12).

= 6 1/2 * 12
convert to improper fraction

= 13/2 * 12
multiply numerators

= (13*12)/2
multiply in parentheses

= 156/2
divide

= 78 miles


ANSWER: (A) 78 miles

Hope this helps! :)
3 0
2 years ago
What digits makes 3,71? Divisible by 3 (connections academy unit test)
wlad13 [49]

Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Let us check which digits will make 371? divisible by 3.

3+7+1+0=11

11 is not divisible by 3.

Now let us check other digits as well.

3+7+1+1=12

12 is divisible by 3.

3+7+1+4=15

15 is also divisible by 3.

3+7+1+7=18

18 is divisible by 3 as well.

Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.

6 0
3 years ago
Cellus<br> The figure below is a rhombus.<br> 630<br> x<br> y = <br> Enter
sleet_krkn [62]

Answer:

y=27

Step-by-step explanation:

6 0
2 years ago
Answer this and I’ll make you Brainly if it’s right!
aliina [53]

Answer:

C

Step-by-step explanation:

f(x)=2x-3

-4-3=-7

-2-3=-5

0-3=-3

2-3=-1

4-3=1

7 0
3 years ago
Read 2 more answers
what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil
dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h  ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h  ∪ m ∪ C)' = 90

53 + n(h  ∪ m ∪ C)' = 90

n(h  ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0
2 years ago
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