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8_murik_8 [283]
3 years ago
9

8) The higher the drag coefficient, the_____ the car will go a)Siower b)Faster

Computers and Technology
2 answers:
Murrr4er [49]3 years ago
6 0

the answer is * slower *

yanalaym [24]3 years ago
5 0
The correct answer is a)Slower
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Write a program that asks the user to enter two numbers,obtains the two numbers from the user and prints the sum,product,
Andru [333]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialization

   float a1,a2;

//display the message

cout<<"Enter the first number: ";

   cin>>a1;  //store the value

   cout<<"Enter the second number: ";

   cin>>a2;   //store the value

   //display the calculation result

   cout<<"The sum is: "<<a1+a2<<endl;

   cout<<"The Subtraction is: "<<a1-a2<<endl;

   cout<<"The product is: "<<a1*a2<<endl;

   cout<<"The Quotient is: "<<a1/a2<<endl;

}

Explanation:

Create the main function and declare the two variables of float but we can enter the integer as well.

display the message on the screen and then store the input enter by the user into the variable using the cin instruction.

the same process for second input as well, display the message and store the input.

after that, print the output of the calculation. the operator '+' is used to add the two numbers like a1+a2, it adds the number stored in the variable.

similarly, the subtraction operator is '-', product '*' and quotient operator '/'.

and finally, we get the desired output.

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3 years ago
Can java scanner not take in a negative input?
algol [13]

Answer:

It can take a negative input

Explanation:

When you declare a variable in Java and you get your input via Scanner library; the Scanner library will accept the input irrespective of whether it's negative or not.

Take for instance, the following segment

<em>Scanner input = new Scanner(System.in);</em>

<em>int userinput = input.nextInt()</em>

<em />

Irrespective of whether userinput is negative or positive, it'll accept it.

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the answer is address bar

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Using a loop and indexed addressing, write code that rotates the members of a 32-bit integer array forward one position. The val
My name is Ann [436]
<h2>Answer:</h2><h2></h2>

//begin class definition

public class Rotator{

    //main method to execute the program

    public static void main(String []args){

       

       //create and initialize an array with hypothetical values

       int [] arr =  {10, 20, 30, 40};

       

       //create a new array that will hold the rotated values

       //it should have the same length as the original array

       int [] new_arr = new int[arr.length];

       

       

       //loop through the original array up until the

       //penultimate value which is given by 'arr.length - 1'

      for(int i = 0; i < arr.length - 1; i++ ){

           //at each cycle, put the element of the

           //original array into the new array

           //one index higher than its index in the

           //original array.

          new_arr[i + 1] = arr[i];

       }

       

       //Now put the last element of the original array

       //into the zeroth index of the new array

       new_arr[0] = arr[arr.length - 1];

       

       

       //print out the new array in a nice format

      System.out.print("[ ");

       for(int j = 0; j < new_arr.length;  j++){

           System.out.print(new_arr[j] + " ");

       }

       System.out.print("]");

       

    }

   

   

}

<h2>Sample Output:</h2>

[ 40 10 20 30 ]

<h2>Explanation:</h2>

The code above is written in Java. It contains comments explaining important parts of the code.  A sample output has also been provided.

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