Question

Solve sin^2x+cos2x-1/4=0

Answer 1

$sin^{2}x + cos2x - \frac{1}{4} = 0$
$sin^{2}x + cos^{2}x - sin^{2}x = \frac{1}{4}$
$cos^{2}x = \frac{1}{4}$
$cos(x) = \pm \frac{1}{2}$

$x = \pm \frac{\pi}{3}$
General solutions: $x = \pi(n - \frac{1}{3})$ and $x = \pi(n + \frac{1}{3})$