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ruslelena [56]
3 years ago
7

Can yall help meh xD

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
4 0
Divide the number by the 100
Valentin [98]3 years ago
3 0

Answer:

Here's the answer

Step-by-step explanation:

Dividing the number by 1000

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What is the measure of ehg?
Jobisdone [24]
(Answer: 120) angle EHF = 90 degrees+30 degrees=120 angle
4 0
2 years ago
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F(x) = -4x2 – x - 3<br> Find f(1)
nadezda [96]

Answer:

-8

Step-by-step explanation:

-4 (1)^2 -(1) -3

-4-1-3=-8

5 0
2 years ago
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PLEASE HELP.
Harrizon [31]

ANSWER

The maximum y-value is 0.

EXPLANATION

The domain of the given absolute value function is (-∞, ∞) .

This means the function is defined for all real values of x.

The range of the function is (-∞, 0].

This can be rewritten as

y \leqslant 0

This means that, the highest y-value on the gray of this absolute value function is 0.

Hence the maximum y-value of the function is 0.

3 0
3 years ago
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Is this relation a function justify your answer
Karo-lina-s [1.5K]
No because there is absolutely no correlation
4 0
2 years ago
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