The slope of the red line that is perpendicular to the green line is: -5/2.
<h3>What are the Slope Values of Perpendicular Lines?</h3>
When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.
<h3>What is the Negative Reciprocal of a Number?</h3>
If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.
Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.
Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.
Negative reciprocal of 2/5 is -5/2.
Therefore, the slope of the red line is: -5/2.
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I think the answer would be the first one
<em>QUESTION:</em>
<em>QUESTION:estimate the equation 12+19.61.</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:</em>
<em>QUESTION:estimate the equation 12+19.61.Answer:12+19.61 =31.61.</em>
Answer:
Step-by-step explanation:
I got you first you want to get some little ceasers
Answer:
If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:
(x,-y)
So we only change the sign of the y-component.
Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.
Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.
The original vertices are:
C = (-3, 7)
D = (0, 7)
E = (0, 10)
F = (-3, 10)
Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:
C' = (-3, -7)
D' = (0, -7)
E' = (0, - 10)
F' = (0, - 10)
Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.
