The standard normal table starts at .5 for z=0, meaning its giving us the integral of the standard gaussian from negative infinity to some positive z. We look for a table entry of 1-.08=.92 and find that at z=1.41.
We knew it was between one and two because the 68-95-99.7 rule tells us one sigma gives a probability of (100-68)/2=16% and two sigma 2.5%, and 8% is in between those.
So our lengths at the ends of the range are
5.13 - 1.41(0.04) = 5.0736
5.13 + 1.41(0.04) = 5.1864
Rounding, 5.07 to 5.19
Because its scary to them
Answer:
62 m/s = 138.7 mi/h
Step-by-step explanation:
62 m/s = 62 x (3600/1000) x (1/1.61)
= 138.7 mi/h
Best Regards!
80/120, divide both numbers by 40.
2/3