Question

If 8^(-z) = 1/8, then what is the value of 8^(z+1)

Answer 1

Answer:

The value is 64.

Step-by-step explanation:

$8^{-z}=\frac{1}{8}\\8^{-z}=8^{-1}\\\implies z=1\\\mbox{so}\\8^{z+1}=8^2=64$