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musickatia [10]
3 years ago
13

Somebody please help. I need to finish this you would be a lifesaver.

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

Step-by-step explanation:

so what you want to do is take -1/4x+2 3/4 and solve for x and once you got what x is plug it in to the second part 1/2^x +1

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Worth 50 points and I will mark brainliest.
olchik [2.2K]

x= -13 , y=11

Step-by-step explanation:

Using elimination method, make the x variable equal to eliminate the variable

-3x - y = -28

2x+ 3y=7

2(-3x-y =28)

3(2x+3y=7)

-6x - 2y =56

6x +9y=21

Apply addition

7y = 77

y=77/7 = 11

Use the value of y=11 in  

2x+ 3y=7

2x +3(11) =7

2x +33 =7

2x=7-33

2x= -26

x= -26/2 = -13

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Solving simultaneous equations :brainly.com/question/12318095

Keywords ; linear combination method,equations, justify,steps

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7 0
3 years ago
What is the scientific notation of 0.0121
jek_recluse [69]
You move to the right, so the exponent is gonna be negative.
1.21 * 10-²
6 0
4 years ago
HELP ME !! find the value of x​
lara [203]

Answer:

ERROR

Step-by-step explanation:

6 0
3 years ago
Solve the equation<br> 7x25=30
oksian1 [2.3K]

Answer:

x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Step-by-step explanation:

Solve for x:

7 x^25 = 30

Hint: | Divide by an appropriate factor to make the coefficient of x^25 equal to 1.

Divide both sides by 7:

x^25 = 30/7

Hint: | Take 25^th roots of both sides.

Taking 25^th roots gives (30/7)^(1/25) times the 25^th roots of unity:

Answer: x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

4 0
4 years ago
What solves for the variable? (g + 7) / 7 = 3<br><br> Thanks :)
sveta [45]

Answer:

g=14

explanation:

4 0
4 years ago
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