The X coordinate has to be 0
Answer:
See explanation
Step-by-step explanation:
Given:
![A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
![B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D)
A. Find AB:
![AB=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]\cdot \left[\begin{array}{cc}-2&1\\3&7\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+4\cdot 3&-2\cdot 1+4\cdot 7\\1\cdot (-2)+3\cdot 3&1\cdot 1+3\cdot 7\end{array}\right]=\left[\begin{array}{cc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=AB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%5Ccdot%20%28-2%29%2B4%5Ccdot%203%26-2%5Ccdot%201%2B4%5Ccdot%207%5C%5C1%5Ccdot%20%28-2%29%2B3%5Ccdot%203%261%5Ccdot%201%2B3%5Ccdot%207%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
B. Find BA:
![BA=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]\cdot \left[\begin{array}{cc}-2&4\\1&3\end{array}\right]=\left[\begin{array}{cc}-2\cdot (-2)+1\cdot 1&-2\cdot 4+1\cdot 3\\3\cdot (-2)+7\cdot 1&3\cdot 4+7\cdot 3\end{array}\right]=\left[\begin{array}{cc}5&-5\\1&33\end{array}\right]](https://tex.z-dn.net/?f=BA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%5Ccdot%20%28-2%29%2B1%5Ccdot%201%26-2%5Ccdot%204%2B1%5Ccdot%203%5C%5C3%5Ccdot%20%28-2%29%2B7%5Ccdot%201%263%5Ccdot%204%2B7%5Ccdot%203%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%26-5%5C%5C1%2633%5Cend%7Barray%7D%5Cright%5D)
C. Answers are not the same
D. Matrices multiplication is not commutastive in general, so

Answer: i) f(-9)= 66
ii)
.
iii) 
Step-by-step explanation:
The given function :
.
i) For f(-9) , the independent variable is x= -9.
Put x= -9 in given function , we get


Thus , f(-9)= 66
ii) For f(x+1) , the independent variable is x= x+1.
Replace x by x+1 in given function , we get
.
![[\because\ (a+b)^2=(a^2+b^2+2ab)]](https://tex.z-dn.net/?f=%5B%5Cbecause%5C%20%28a%2Bb%29%5E2%3D%28a%5E2%2Bb%5E2%2B2ab%29%5D)


Thus ,
.
iii)For f(-x) , the independent variable is x=-x.
Replace x by -x in given function , we get
.
[∵ (+)(-)=(-)]
Thus , 
Answer:
Step-by-step explanation:
hello :
-5x+10x+3=5x+6
(-5x+10x)+3=5x+6
5x+3 = 5x+6
5x+3 -5x= 5x+6-5x
3 = 6.....(false)
no solutions in R
Answer:
(x + 3)(2x + 5)
Step-by-step explanation:
Given
2x² + 6x + 5x + 15 ← grouping the terms
= (2x² + 6x) + (5x + 15) ← factor each group
= 2x(x + 3) + 5(x + 3) ← factor out (x + 3) from each term
= (x + 3)(2x + 5) ← in factored form