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2 years ago

What is the independent variable of an equation?

Mathematics

1 answer:

wolverine [178]2 years ago

6 0

X is. Y is the dependent variable cause most of the time u plug in x.

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Need the answer please 3 please answer

photoshop1234 [79]

Answer:

Positive 8

Step-by-step explanation:

The end value of -(-8) would be positive eight because when you multiply a negative by a negative, you get a positive value.

This question is essentially -1 times -8, which would equal 8

(The answer would be: 8)

I hope this helps!

7 0

2 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

$= x {}^{9} y {}^{ - 8}$

$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4} n {}^{ - 1} }{m {}^{ - 5}n {}^{3} } = - 2m {}^{9} n {}^{ - 4}$

$= - \frac{2m {}^{9} }{n {}^{4} }$

14.

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

$( - {x}^{5} y {}^{ - 2} ) {}^{3} = - x {}^{15} y {}^{ - 6}$

$- \frac{x {}^{15} }{ {y}^{6} }$

15.

$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

16.

$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

6 0

2 years ago

Pls help w math !

Vsevolod [243]

The answer is -7
4+-7=-3

3 0

2 years ago

Read 2 more answers

If you were to graph the linear equation 4x+6y=−12 on the semester test, you would need to determine the x- and y-intercepts, pl

goblinko [34]

The x intercept is -3, and the y intercept is -2

Step-by-step explanation:

The equation given is 4x+6y= -12

Rewrite the equation in slope intercept form of y=mx +c where c is the y intercept

y=mx+c

6y=-4x-12

y= -4/6 x -12/6

y=-2/3x -2

c= -2

To get x intercept replace value of y in the equation with 0;

y= -2/3 x -2

0= -2/3 x -2

2= -2/3 x

2*3=-2x

6=-2x

6/-2 =x

-3 =x

x intercept is -3

Learn More

Linear equations : brainly.com/question/9994201

Keywords : graph, linear equation, intercepts, plot

#LearnwithBrainly

4 0

2 years ago

Read 2 more answers

PLEASE HELP! Brainliest answer for first correct answer...

trasher [3.6K]

check picture below

8 0

3 years ago