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OlgaM077 [116]
3 years ago
10

Someone help me with this ASAP!AKA WITH PART 3!!

Mathematics
2 answers:
valina [46]3 years ago
6 0

14.2 if u need fraction it is 14 1/5

natulia [17]3 years ago
3 0

29 minutes I believe

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.<br> Evaluate ƒ(x) = 3x + 8 for x = 1.<br><br><br> 3<br><br><br> 5<br><br><br> 11<br><br><br> –11
rodikova [14]

Answer:

11

Step-by-step explanation:

Replace the variable xx with −1-1 in the expression.

f(−1)=−3⋅−1+8f(-1)=-3⋅-1+8

Simplify the result.

Tap for fewer steps...

Multiply −3-3 by −1-1.

f(−1)=3+8f(-1)=3+8

Add 33 and 88.

f(−1)=11f(-1)=11

The final answer is 1111.

=11

I want brainless pleased

8 0
2 years ago
A bank's loan officer rates applicants using their FICO credit score. The ratings are normally distributed with a mean of 711 an
tekilochka [14]

Answer:

The answer is "778"

Step-by-step explanation:

Given value:

\to \mu= 711\\\\\to \sigma= 80\\\\\to P(Z >0.84) = 0.20\\\\\to z = 0.84

The formula for z-score:

\to x = z \times  \sigma + \mu \\\\\to x = 0.84 \times 80 + 711 \\\\ \to x=67.2 +711\\\\ \to x=  778.2\\\\ \to x= 778

6 0
3 years ago
A cylinder has a radius of 6 inches and a height of 2 feet. Which of the following should be done first in order to find the vol
zvonat [6]
The significant components, the radius and the height, are in inches and feet respectively, you'd need to convert them both to the same unit, whichever it may be, meters or feet or inches or millimeters, so long is the same, then use the volume of a cylinder equation to get it.
7 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
9 more than 2 multiplied by f
Andrej [43]
(2+9)*f
= 11*f

The final answer is 11f~
6 0
3 years ago
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