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riadik2000 [5.3K]
2 years ago
11

Find the scale factor of the similar shapes below.

Mathematics
1 answer:
timofeeve [1]2 years ago
5 0

Answer:

x=12 and the scale factor is 1.5

Step-by-step explanation:

From D' to F' is 7.5 and from D to F is 5cm the difference is 2.5. From F' to E' is x and from F to E is 8. This is just understanding what you can see. You find x by figuring out the ratio from 5 to 7.5 is and 8 to x or vise versa.  It depends which way you are going. I think you are going from E,D,F to E',D',F'. So from 5cm to 7.5 cm. This is 1.5 because you are dividing 7.5/5. If you needed to find x, it would be 12.

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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
How to covert 11 pi over 12 to degrees
Readme [11.4K]
When you convert 11pi over 12 in to degrees, you get 165°
4 0
3 years ago
Show work please help
Snezhnost [94]

Answer:

20 yd^2

Step-by-step explanation:

Your work is partially correct.

Assuming that the sides marked 8 yds and 2 yds are parallel, then the area of the trapezoid is

A =    ( 8 yds + 2 yds)

        ------------------------ * 4  =  20 yd^2

                      2

4 0
3 years ago
Solve each equation.<br> 3) 4= 2x + 3.x
Andrej [43]

Answer:

Step-by-step explanation:

2x+3x=4

5x=4

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2 years ago
Read 2 more answers
Help please!!! I only have 10 minutes!!
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I think 0.7 would be it
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2 years ago
Read 2 more answers
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