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andre [41]
3 years ago
12

Jessiie saves $6 each week. In how many weeks will she have saved at least $50​

Mathematics
2 answers:
diamong [38]3 years ago
5 0
The answer is 9 because 6 times 9 is 54 and the question is asking how many weeks it will take for her to earn at least 50
AleksandrR [38]3 years ago
4 0

Answer:

9 weeks

Step-by-step explanation:

She will only save 48$ during the 8th week, but she will save 54$ by her 9th week.

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Bumek [7]
The answer would be 313
7 0
4 years ago
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A coin is tossed 10 times. True or false, and explain: (a) The chance of getting 10 heads in a row is 1/1,024. (b) Given that th
Llana [10]

Answer:

a and b both are true.

Step-by-step explanation:

Given : A coin is tossed 10 times.

To find : True or false, and explain ?

Solution :

(a) The chance of getting 10 heads in a row is \frac{1}{1024}

Coin has two face head and tail.

The probability of getting head is P(H)=\frac{1}{2}

The probability of getting 10 heads in a row is

P=(P(H))^{10}

P=(\frac{1}{2})^{10}

P=\frac{1}{1024}

The chance of getting 10 heads in a row is \frac{1}{1024} is true.

(b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is \frac{1}{2}.

The probability of getting 10 heads in a row is P_1=(\frac{1}{2})^{10}

The probability of getting 9 tosses were heads is P_2=(\frac{1}{2})^{9}

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is given by,

P=\frac{P_1}{P_2}

P=\frac{(\frac{1}{2})^{10}}{(\frac{1}{2})^{9}}

P=(\frac{1}{2})^{10-9}

P=\frac{1}{2}

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is \frac{1}{2} is true.

3 0
3 years ago
What is the next term of the arithmetic sequence 6, 10, 14, 18, ...?
Zinaida [17]
22 bc the rule is +4
8 0
3 years ago
I need help on 90-93
Natasha_Volkova [10]

Answer:

negative 3

Step-by-step explanation:

because 90_93

8 0
3 years ago
A coffee shop collected the following information regarding purchases from 110 of its customers 59 purchased coffee 39 purchased
Andrej [43]

Answer:

Let X be the number of customer purchased coffee

Let Y be the number of customer purchased donuts

Then X\cap Y is the number of customer purchased both coffee and donuts

X\cup Y  is the number of customer purchased both coffee or donuts

<em><u>The Number of customers purchased  only Coffee:</u></em>

Number of customers purchased  only donuts =n(X -Y)

n( X -Y) = n(X) - n(X \cap Y)

n(X-Y) = 59 -16

n(Y - X) = 43

<em><u>The Number of customers purchased  only donuts:</u></em>

Number of customers purchased  only donuts =n(Y -X)

n(Y - X) = n(Y) - n(X \cap Y)

n(Y - X) = 39 -16

n(Y - X) = 23

<u>The Number of customers did not purchase either of these items:</u>

Number of customers did not purchase either of these items = n(X\cup Y)^{\prime}

First lets find   n(X\cup Y)

n(X\cup Y) = n(X) +  n(Y) - n( X \cap Y)

n(X\cup Y) = 59 + 39 - 16

n(X\cup Y)  = 82

n(X\cup Y)^{\prime}  =110 -  n(X\cup Y)  = 28

5 0
4 years ago
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