Answer:
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
Step-by-step explanation:
To find the total number of canned foods brought in by the three grades, we will have to add the number of canned foods brought by each of the grades to each other. Careful attention has to be paid to the decimal points.
Canned foods brought by 6th graders: 5.75 boxes
Canned foods brought by 7th graders: 6.5 boxes
Canned foods brought by 6th graders: 7/1.3 boxes
We may have a slight challenge adding in 7/1.3 boxes to the other figures. What we can do now is to evaluate it to a decimal value by dividing it up.
7/ 1.3 will be the same thing as 7 divided by 1.3 = 5.38 boxes.
hence, we have 5.75 +6.5+ 5.38= 17.63 boxes
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
Answer:
Third choice is the correct one
Explanation:
No fraction can have a denominator = 0 because this would make it undefined.
Therefore, the solution would be all the real values except for those that make the denominator = 0
Let's check the terms in the denominator:
i. c-3 = 0 at c = 3
ii. c = 0
iii. c(c-3) = 0 at c = 0 or c = 3
Therefore 0 and 3 are the values that would make the denominator zero.
Based on the above, the solution is all real numbers except 0 and 3
Hope this helps :)
Answer: 
Step-by-step explanation:
The equation is 
.
To find the value of the variable "x" in terms of "y", you need to apply the Division property of equality and divide both sides of the equation by "2a". Then:
You know that the costants "a" and "b" are equal (
), then:
Knowingt this, you can simplify.
Therefore, you get that the value of "x" in terms of "y" is:
Answer:
1.42
Step-by-step explanation:
1.3+6/50
1.3 +0.12
1.42
The answer is -9. Hope I helped
