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Rudiy27
4 years ago
6

Classify each square root as rational or irrational. √4√9 √12 √17 √20 √25

Mathematics
1 answer:
Sati [7]4 years ago
3 0

Answer:

√4 rational

√9 rational

√12 irrational

√17 irrational

√20 irrational

√25 rational

Step-by-step explanation:

2² = 4

3²=9

√12 = 2√3 ⇒ p²/q² = 3

p and q are prims (irreducible fraction), therefore has maximum common divisor 1, and belong to the Integers.

p>q

p²=3q² ⇒ p is multiple of 3

If p² is divisible for 3 and the MDC (p and q) is 1, p²=3 and q=1. But it is absurd, because 3 is not a perfect square.

the rest is tasted the same way, but it will take too long so I won't put ...

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7 0
3 years ago
Hugo wants to make a sandwich using
aniked [119]

Answer:

a) WCK, WTM, WTK, BCM, BCK, BTM, BTK.

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Step-by-step explanation:

a)

For this answer we just need to write all possibilities of sandwiches, so we can use the options given to create all the sandwiches, besides the one given:

(WCM given), WCK, WTM, WTK, BCM, BCK, BTM, BTK.

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6 0
3 years ago
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cupoosta [38]

Answer:

It is C.

First of all, we can see that angle 1 is 132 degrees because they are the same angles/measurements. Therefore, angle 1 and angle 3 are also supplementary as they create a straight line, or 180 degree angle. As they are supplementary, angle 1 + angle 3 = 180. We know that angle 1 is 132, so we have 132 + angle 3 = 180, and angle 3 is 42 degrees.

7 0
3 years ago
Find the zeros (roots) of the following equations.
saw5 [17]
Hello,

f(1)=2-9+12-12+10-3=0 ===>(x-1)*....
f(3)=2*3^5-9*3^4+12*3^3-12*3^2+10*3-3=0 ===> (x-3)*....
f(1/2)=2*(1/2)^5-9*(1/2)^4+12*(1/2)^3-12*(1/2)^2+10*1/2-3=0 ===>(2x-1)*...

f(x)=(x-1)(x-3)*(2x-1)*(x²+1)
In C, x=i ou x=-i

Zeros are 1/2,1,3,i,-i


6 0
4 years ago
Read 2 more answers
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