Use the quadratic formula to solve for x 8x^2+7x+1=0 plz help
2 answers:
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9514 1404 393
Answer:
(x, y) = (-1, -3)
Step-by-step explanation:
The equations are "consistent" and "not dependent." This will be the case whenever the ratios of x- and y-coefficients are different.
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We can solve this by "elimination" by multiplying the first equation by -4 and adding the result of the second equation being multiplied by 7.
-4(2x -7y) +7(7x -4y) = -4(19) +7(5)
-8x +28y +49x -28y = -76 +35 . . . . eliminate parentheses
41x = -41 . . . . . simplify
x = -1 . . . . . . . divide by 41
Using the second equation, we find y to be ...
(7x -5)/4 = y = (7(-1) -5)/4 = -12/4 = -3
So, the solution is (x, y) = (-1, -3).
Answer:
⇒ answer 1
Step-by-step explanation:
* Lets explain how to find the inverse of a function
- To find the inverse of a function :
# Write y = f(x)
# Switch the x and y
# Solve to find the new y
# The new y is
* Lets solve the problem
∵ f(x) = 2x + 1
- Put y = f(x)
∴ y = 2x + 1
- Switch x and y
∴ x = 2y + 1
- Solve to find the new y
∵ x = 2y + 1
- Subtract 1 from both sides
∴ x - 1 = 2y
- Divide both sides by 2
∴ (x - 1)/2 = y
- Divide each term in the left hand side by 2
∴ y = 1/2 x - 1/2
- Replace y by
∴
* The inverse of the function is