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maxonik [38]
3 years ago
6

Juan wants to find the mode of the data set below.

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

A line plot shows all the numbers lined up and will easily show what the mode, or most occurring number is. A stem and leaf plot shows this, but is less clear and is more used for what numbers are.

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The value of
marusya05 [52]

\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

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\sf :\implies x = 1 + \sqrt{2}

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Express your answer in scientific notation. 4.9\cdot 10^{5} - 5.8 \cdot 10^{4} =4.9⋅10 5 −5.8⋅10 4 =4, point, 9, dot, 10, start
tatyana61 [14]

Answer:

4.32*10^{5}

Step-by-step explanation:

Given the expression 4.9*10^{5}-5.8*10^{4}, to solve the expression, we need to write both scientific notation to the same power of 10.

5.8*10^{4} is \ expressed\  as \ 0.58*10^{5}

The expression above becomes 4.9*10^{5}-0.58*10^{5}. On taking the difference;

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The final expression gives the right answer

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