The value of W when V = 9 is 405
<h3>How to solve for W?</h3>
The variation is a direct variation from W to V^2.
This means that:
W = kV^2
Where k is the constant of variation.
W = 320 when V = 8 means that:
320 = k * 8^2
Evaluate
320 = 64k
Divide both sides by 64
k = 5
Substitute k = 5 in W = kV^2
W = 5V^2
When V = 9, we have:
W = 5 * 9^2
Evaluate
W = 405
Hence, the value of W when V = 9 is 405
Read more about direct variation at:
brainly.com/question/6499629
#SPJ1
Answer:
question 9
= –12
while question 11=, x= –72
Step-by-step explanation:
question 9=
u= –16+4= –12
question 11=
cross multiplication
x = -36 multiplied by 2 =
-72
I HOPE THIS HELPED IF WRONG IM SORRY
2πr/2r = <span>π This is the ratio of the Circumference : Diameter </span>
Answer:
<h2>x = -11</h2>
Step-by-step explanation:
In algebra, the goal is always to isolate the variable, so that its value can be determined.
<h3>Step 1: Add x</h3>
6 + x = -5
<h3>Step 2: Subtract 6</h3>
x = -11
<h3>Step 3: Check</h3>
6 = -5 - -11
6 = -5 + 11
6 = 6 ✔
<h3>Step 4: Answer</h3>
x = -11
I'm always happy to help :)
