Answer:
x=5 use its a great source
Answer:
a) 95 % confidence interval for the mean estimate of the average income of all U.S. households based on the information
(58,808 ,71,192)
<u> </u>Step-by-step explanation
<u>Explanation</u>:-
Given data assume the 25 adults in the study can be considered an SRS from the population of all adult citizens of the United States.
Given sample size 'n' =25
The mean estimate x⁻ = $ 65 , 000
sample standard deviation 's' = $ 15 , 000
Degrees of freedom γ= n-1 =25-1=24
The tabulated value t = 2.0639 (check t- table blue mark) at 0.05 level of significance with 24 degrees of freedom.
<u>Step(ii):-</u>
<u>95 % confidence interval for the mean </u>
(65,000-6191.7 ,65,000+6191.7)
(58,808 ,71,192)
<u>Conclusion</u>:-
95 % confidence interval for the mean estimate of the average income of all U.S. households based on the information
(58,808 ,71,192)
<u> </u>
Given the function f(x) = log 0.75x
The interval that contains all the x-values must be greater than 1.333
For the function to be positive, the expression 0.75x must be greater than and equal to 1 as shown:
Divide both sides by 0.75
0.75x/0.75 ≥ 1/0.75
x ≥ 1/0.75
x ≥ 1.333
Hence the interval that contains all the x-values must be greater than 1.333
Learn more on inequalities here: brainly.com/question/11613554
Answer: 5,499,187,200
<u>Step-by-step explanation:</u>
A coin is tossed 5 times.
There are two options (heads or tails) so the possible outcomes are: 2⁵
A six-sided die is rolled 4 times.
There are six options so the possible outcomes are: 6⁴
A group of 3 cards are drawn (without replacement).
The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50
Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:
2⁵ x 6⁴ x 52 x 51 x 50
= 32 x 1296 x 132,600
= 5,499,187,200
Answer:
if you're talking about which number is in between 9 and 45 there's only one number 27