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anzhelika [568]
3 years ago
14

Ill MARK BRAINLIEST

Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0

Answer:

The answer is C. 1 2/5 cups of oats

Step-by-step explanation:

Ok so the bakery uses 3 3/5 cups of oats for 2 4/7 POUNDS of cookies.

You need to find the unit price.

So to get from 2 4/7 to 1, you need to divide 2 4/7 by 2 4/7

You need to do the same thing to 3 3/5 cups.

3 3/5 as an improper fraction is 18/5

2 4/7 as an improper fraction is 18/7

Now to divide you need to keep, change, and flip

keep the 18/5, change the sign to multiplication, and flip the 18/7 to 7/18

18/5*7/18=7/5

7/5 or 1 2/5 pounds of outs are required to make 1 pound of oatmeal cookies

Gnoma [55]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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Easy one - giving brainly if correct - show work.
Maksim231197 [3]

Answer:

a = 9.6 b = 11.2

Step-by-step explanation:

10 percent of 8 is .8

8 + (8 x .1) = 8.8

8.8 + .8 = 9.6

She will be paid 9.6 dollars after 1 full year of working, because working for one year is 12 months, and thats 10 percent of 8 twice. You can also put that as 20 percent of 8, aka 1.6

When you do 8+1.6 it equals 9.6

For the second part, that is 24 months, so 10 percent of 8 4 times. .8+.8+.8+.8 = 3.2

8+3.2 = 11.2

She will be paid 11.2 dollars after 2 full years of working.

Your answer isnt wrong, I dont know why your teacher is saying it is.

4 0
3 years ago
In Exercises 6 and 7, use the given measure to find the missing value in each data set. 6. The mean of the ages of 5 brothers is
strojnjashka [21]

Solution

Problem 6

For this case we can do this:

12, 16,__, 14, 8, 7

We can solve for x like this:

\frac{12+16+x+14+8+7}{6}=13x=13\cdot6-(12+16+14+8+7)=21

Problem 7

F

7 0
1 year ago
Choose an entree (steak, chicken, fish, or tofu), a side (mac & cheese, green beans, french fries, or bread), and a drink (w
notka56 [123]
You have steak Mac water or steak mac water, etc etc...
4 0
3 years ago
What does y=5x+4 look like on slope intercept form?
valentina_108 [34]
Beachside it is supposed to be 619 into that form
4 0
3 years ago
Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17
ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P(V^{C}∩W^{C}) , where P(V^{C}) is the probability that the event V doesn't happen and P(W^{C}) is the probability that the event W doesn't happen.

P(V^{C})= 1-P(V) = 1-0.17 = 0.83

P(W^{C})=1-P(W) = 1-0.05 = 0.95

Since V^{C} and W^{C} aren't mutually exclusive events, then:

P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

P(V^{C}∩W^{C})= P(V^{C}) + P(W^{C}) - P(V^{C}∪W^{C})

Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

Finally:

P(V^{C}∩W^{C}) = 0.83 + 0.95 - 0.96 = 0.82

5 0
3 years ago
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