QUESTION A
The given inequality is
Add 1 to both sides of the inequality to obtain;
Answer: 2.
, open dot at 6 and shaded to the right.(A)
QUESTION B.
The given inequality is
.
Divide both sides by 2;
.
.
Answer: 5.
, closed dot at 3 and shaded to the left(B).
QUESTION C
The given inequality is
Add 7 to both sides to get;
Answer: 7.
, open dot at 3 and shaded to the right.(C)
QUESTION D
We want to solve;
Divide through by -2 and reverse the inequality sign;
Answer; 3.
Open dot at -3 and shaded to the right. (D)
QUESTION E
We have
Divide through by -4 and reverse the sign.
or
Answer: 6.
open dot at -1, and shaded to the left(E)
QUESTION F
The given inequality is
Add -3 to both sides to get;
Divide both sides of the inequality by -2 and reverse the sign;
Answer:9.
, open dot at 5 and shaded to the right(F)
QUESTION G
The given inequality is



Divide by 5

Answer ; 10.
, closed dot at 2 and shaded to the right(G)
QUESTION H
We have 
Expand the bracket to get;

Group similar terms to get;

Simplify

Divide through by -5 and reverse the sign;

Answer: 1.
Open dot at 18/5 and shaded to the left(H)
QUESTION I
We have
.


Divide by -2 and reverse the sign;

Answer: 8.
, open dot at 1 and shaded to the right(I)
J. The given inequality 
Expand the bracket to get;

Group like terms to get;


Divide by -1 and reverse the sign to get;

Answer; 4.
, open dot at 5 and shaded to the left.(J)