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Dominik [7]
3 years ago
11

How many flowers spaced every 3 inches are needed to surround a circular garden with a 30 foot radius? Round all circumference a

nd area calculations to the nearest whole number
Mathematics
1 answer:
icang [17]3 years ago
6 0

Answer:

756 flowers

Step-by-step explanation:

First you will need to find the circumference of the garden with circumference formula (2πr). The circumference is 188.5 and rounded to nearest whole number is 189. You then need to put that into inches since it is in feet, it is 2268 inches. Lastly, you divide that by three to get the amount of flowers needed.

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A drama club earns $1040 from a production. A total of 64 adult tickets and and 132 student tickets are sold. An adult ticket co
CaHeK987 [17]
A=adult ticket           s=student ticket                         

64a+132s=$1040
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2 years ago
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At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green
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4 0
3 years ago
Escribe la posición del móvil si el diámetro de la trayectoria es de 10 m y la distancia recorrida es de 190 m
lions [1.4K]

Step-by-step explanation:

La posici´on de una part´ıcula que se mueve unidimensionalmente esta definida por la ecuaci´on:

x(t) = 2t

3 − 15t

2 + 24t + 4 donde 0x

0 y

0

t

0

se expresan en metros y segundos respectivamente. Determine:

a. ¿Cu´ando la velocidad es cero?

b. La posici´on y la distancia total recorrida cuando la aceleraci´on es cero.

Soluci´on:

a. Recordemos que:

v(t) =

dx

dt =

d

dt(2t

3 − 15t

2 + 24t + 4) = 6t

2 − 30t + 24

Sea t

0

el tiempo en que la velocidad se anula, entonces v(t

0

) = 0.

De este modo:

0 = v(t

0

) = 6(t

0

)

2 − 30(t

0

) + 24 = 6[(t

0

)

2 − 5(t

0

) + 4] = 6[(t

0

) − 4][(t

0

) − 1]

As´ı tenemos que:

t

0

1 = 4, t

0

2 = 1

De este modo, tenemos que la velocidad se anula al primer segundo y a los cuatro segundos.

b. Recordemos que:

a(t) =

dv

dt =

d

dt(6t

2 − 30t + 24) = 12t − 30

Ahora sea t

0

el instante en que la aceleraci´on se anula, entonces a(t

0

) = 0

Ahora:

0 = a(t

0

) = 12t

0 − 30

As´ı tenemos que: t

0 =

30

12 =

5

2

Por lo tanto, la posici´on en este instante es:

x(t

0

) = x

5

2

= 2

5

2

3 − 15

5

2

2 + 24

5

2

+ 4 = 125

4 − 3

125

4 + 60 + 4 = −2

125

4 + 64 = −

125

2 +

128

2 =

3

2

De este modo, la posici´on de la part´ıcula cuando la aceleraci´on es cero es de 3

2 metros.

Adem´as la distancia total recorrida esta dada por:

distancia = |x(t

0

) − x(0)| = |

3

2 − 4| =

5

2

Finalmente la distancia total recorrida es: 5

5 0
2 years ago
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