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2 years ago

Timothy brought in brownies for his class on his birthday.

Mathematics

1 answer:

IgorC [24]2 years ago

8 0

Answer:

Incomplete problem - reword

Step-by-step explanation:

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Find the length of AB. Leave

vovikov84 [41]

Answer:

Step-by-step explanation:

<em>See attachment for correct format of question.</em>

Given

From the attachment, we have that

θ = 20°

Radius, r = 27

Required

Find length of AB

AB is an arc and it's length can be calculated using arc length formula.

$Length = \frac{\theta}{360} * 2\pi r$

<em>Substitute 20 for θ and 27 for r</em>

$Length = \frac{20}{360} * 2\pi *27$

$Length = \frac{20 * 2\pi * 27}{360}$

$Length = \frac{1080 \pi}{360}$

$Length = 3\pi$

Hence, the length of arc AB is terms of π is 3π

3 0

3 years ago

What is the volume of the oblique cube

serious [3.7K]

Answer:

$\large\boxed{V=\dfrac{1600\pi}{3}\ cm^3}$

Step-by-step explanation:

The formula of a volume of a cone:

$V=\dfrac{1}{3}\pi r^2H$

r - radius

H - height

We have r = 10cm and H = 16cm. Substitute:

$V=\dfrac{1}{3}\pi(10^2)(16)=\dfrac{1}{3}\pi(100)(16)=\dfrac{1600\pi}{3}\ cm^3$

6 0

3 years ago

Someone please help.

umka21 [38]

Let's go:

$\frac{y}{3} = \frac{27}{y} \\\\ y^2 = 27.3 \\\ y^2 = 81 \\\ y = \sqrt{81} \\\ y = 9$

I hope I helped you.

8 0

3 years ago

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression $2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)$

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

$= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\$

Then we find the LCM of the resulting function

$= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\= \frac{7x}{10} + 2\frac{1}{2}y+6\\$

The final expression gives the required answer

7 0

2 years ago

Math math uhhh i no like math<br> n33d h319 pls

IrinaK [193]

hope it helps✓✓✓✓✓✓✓✓✓

5 0

2 years ago