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3 years ago

Help please!

Mathematics

1 answer:

Savatey [412]3 years ago

7 0

Answer:

The new drug appears to reduce insomnia since the re-randomized mean differences are close to the mean difference found between the two groups studied.

Step-by-step explanation:

The group given the new drug reported an average of 3.3 nights they suffered insomnia a month. Therefore the mean of this group is 3.3.

On the other hand, the control group receiving the placebo reported an average of 9.5 nights they suffered insomnia a month. Therefore, the mean of this control group is 9.5.

The population mean difference between these two groups is thus;

9.5 - 3.3 = 6.2

This difference is very significant inferring that the new drug appears to reduce insomnia. Nevertheless, this mean difference is considerably close to the difference of the means from re randomization. Therefore we can conclude that,

The new drug appears to reduce insomnia since the re-randomized mean differences are close to the mean difference found between the two groups studied.

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icang [17]

r+s^2

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3 years ago

Gino wants to purchase a phone that costs $758 and a case that costs $33.80. If the sales tax is 10%, what is the total amount G

Harlamova29_29 [7]

Answer:

870.98

Step-by-step explanation:

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2 years ago

Challenge Yael used to have a square garage with 370 ft ^2of floor space. She recently built an

Yuki888 [10]

Scale factor of area is the square of the scale factor of length

The required values are;

The length of one sides of the garage was originally approximately 19.2 ft.

The length of one of the sides of the garage is now approximately 23.6 feet long

The percentage increase in length is approximately 22.5 %

Reason:

The given parameters are;

The area of the square garage = 370 ft.²

The area of the new garage has 50% more space

Required;

Part A

The initial side length

The initial side length, given to the nearest tenth, s, is the square root of the area, A, given as follows;

s = √(370 ft.²) ≈ 19.2 ft.

Part B

The side was increased by 50%, to give,

370 + 0.5×370 = 555

The new area of the garage = 555 ft.²

The side length of the new garage, s = √(555) ≈ 23.6

The side of the garage now is 23.6 ft.

Part C

The percentage increase is given as follows;

$The \ percentage \ increase \ in \ length = \dfrac{New \ length - Initial \ length}{Initial \ length }$

$The \ percentage \ increase \ in \ length = \dfrac{\sqrt{555} - \sqrt{370} }{\sqrt{370} } \times 100 \approx 22.5 \%$

The percentage increase in length of the side of the garage is approximately 22.5 %

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3 years ago

MAKE SURE TO SHOW WORK solve for c: a=7b+8c+9d-10

Slav-nsk [51]

a=7b+8c+9d-10
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c = (a - 7b - 9d + 10) / 8

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3 years ago

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castortr0y [4]

Answer:

60,500

Step-by-step explanation:

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3 years ago