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KatRina [158]
2 years ago
14

R + s² at r = 4, s = 1 ( Pls show work) AND NO LINKS THX UwU

Mathematics
1 answer:
icang [17]2 years ago
5 0

r+s^2

4+1^2

4+2

6

Hopefully this helped

Cani get the brainliest please

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Machine A prints 16 pages more than Machine B in every minute. Machine A and Machine B print a total of 608 pages in 4 minutes.
sweet [91]

1) So the ratio of Machine A to B is x + 16 : x (x being the paper printed in machine b).

2) This is in 4 minutes so every minute it will be 152.

2) So x + 16 + x = 152, or 2x + 16 = 152.

3) So to find x, we can subtract 16 from both sides. 2x = 136

4) Now we just divide both sides by 2 to get x = 68.

5) So machine A will be 68 + 16 = 84.

=  84

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

3 0
2 years ago
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Robs age is twice the sum of Julias age and 10. Rob is 24 years old. Write and solve an equation to determine Julia's age.
levacccp [35]

Answer:

yo momma

Step-by-step explanation:

4 0
2 years ago
Suppose demand d for a company's product at cost x is predicted by the
11111nata11111 [884]

Answer:

0.36x ² + 815.04x + 11,340

Step-by-step explanation:

Revenue = price × quantity

p(x) = x+14

d(x) = 0.36x + 810

Revenue = price × quantity

= (x + 14) * (0.36x + 810)

= 0.36x² + 810x + 5.04x + 11,340

= 0.36x ² + 815.04x + 11,340

Company's revenue = 0.36x ² + 815.04x + 11,340

3 0
3 years ago
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
Please help, today's due. Maths lesson is postulate.
zhenek [66]
You need to put everything to one side and equal to 120. Then you combine all like terms.
then you subtract 24 with 120. You get 94/24=4

10x+6x+16+8x+8=120
24x+24=120
-24 -24
____________
24x=96
/24 /24
X=4
8 0
2 years ago
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