Answer:
Step-by-step explanation:
Volume of tank is 3000L.
Mass of salt is 15kg
Input rate of water is 30L/min
dV/dt=30L/min
Let y(t) be the amount of salt at any time
Then,
dy/dt = input rate - output rate.
The input rate is zero since only water is added and not salt solution
Now, output rate.
Concentrate on of the salt in the tank at any time (t) is given as
Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000
dy/dt= dV/dt × dM/dV
dy/dt=30×y/3000
dy/dt=y/100
Applying variable separation to solve the ODE
1/y dy=0.01dt
Integrate both side
∫ 1/y dy = ∫ 0.01dt
In(y)= 0.01t + A, .A is constant
Take exponential of both side
y=exp(0.01t+A)
y=exp(0.01t)exp(A)
exp(A) is another constant let say C
y(t)=Cexp(0.01t)
The initial condition given
At t=0 y=15kg
15=Cexp(0)
Therefore, C=15
Then, the solution becomes
y(t) = 15exp(0.01t)
At any time that is the mass.
How to solve:
( x , y )
Plug the values in to the equation and solve
-3x+5y=2x+3y
(2,4) plugged in would be
-3(2)+5(4)=2(2)+3(4)
All you have to do is solve this and if the two sides are not equal(like 4=20), then it is not a solution. Just plug in (3,3) next.
Hope this helped!!!
Innermost orbitals have the least amount of energy
There are 20 saxophone players. For every 6 flutes there are 4 saxophones so if you do 6x5=30. Then you would do 4x5 and get 20. 30 flutes plus 20 saxophones = 50 total students
I think the answer is 5 because you add the 1/2 and the other 1/2 leave the for alone that will give you 5
Example: 1/2+1/2=1+4=5