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BlackZzzverrR [31]
3 years ago
15

Find the slope of each line

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer: 7/3

Step-by-step explanation: From the leftmost, lower point to the uppermost point, you move upwards 7, and rightward 3. Slope is vertical movement over horizontal, giving 7/3.

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A sphere is dilated by a scale factor of 1.5 to create a new sphere. How does the volume of the new sphere compare with the volu
SashulF [63]

Answer:

The volume of new sphere is 3.375 times greater than the volume of old sphere

Step-by-step explanation:

Let r be the radius of old sphere. This old  sphere is dilated by a scale factor of 1.5 to create a new sphere, so the radius of new sphere is R=1.5r.

The volume of the sphere can be calculated using formula

V=\dfrac{4}{3}\pi r^3

Hence,

V_{old}=\dfrac{4}{3}\pi r^3\\ \\V_{new}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi (1.5r)^3\\ \\\dfrac{V_{new}}{V_{old}}=\dfrac{\dfrac{4}{3}\pi (1.5r)^3}{\dfrac{4}{3}\pi r^3}=1.5^3=3.375

6 0
3 years ago
There are four quarters in a dollar. How many quarters are there in eleven dollars?
Elan Coil [88]

Answer:

44

Step-by-step explanation:

There are 4 quarters in a dollar.

"How many quarters are there in eleven (11) dollars?"

4 x 11 = 44

There are 44 quarters in eleven dollars.

5 0
1 year ago
Read 2 more answers
A tailor used 2 meters of string to make 10 Halloween masks. He used ___ of a meter for each mask.
Lostsunrise [7]
2 meters were used in 10 masks

2meters/10masks= 0.2meters per mask
5 0
3 years ago
Read 2 more answers
Angad was thinking of a number. Angad adds 11, then divides by 8 to get an answer of 5. What was the original number?
galben [10]

Answer:

29

Step-by-step explanation:

x+11÷8=5

5 × 8 = 40

40- 11 = 29

29 + 11 ÷ 8 =5

5 0
2 years ago
The gradiant y=2x³-5x+1 at point (2,7)​
olga2289 [7]

Given:

The equation of the curve is:

y=2x^3-5x+1

To find:

The gradient (slope) of the given curve at point (2,7).

Solution:

We have,

y=2x^3-5x+1

Differentiate the given equation with respect to x.

y=2(3x^2)-5(1)+(0)

y'=6x^2-5

Now we need to find the value of this derivative at (2,7).

y'_{(2,7)}=6(2)^2-5

y'_{(2,7)}=6(4)-5

y'_{(2,7)}=24-5

y'_{(2,7)}=19

Therefore, the gradient (slope) of the given curve at point (2,7) is 19.

8 0
2 years ago
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