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musickatia [10]
2 years ago
14

The number of dogs to the number of cats at the pet rescue is 3:5. If there are a total of 65 cats at the rescue center, how man

y dogs are there at the center.
Mathematics
2 answers:
Marat540 [252]2 years ago
7 0

If the dogs represent 3 and the cats represent 5 then there are 39 dogs.

snow_lady [41]2 years ago
6 0
_:65
65/5=13
13*3=39
39:65
39 dogs
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John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo
yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6

3 0
1 year ago
58 pts!!!! <br> Write an equation of the line in slope intercept form.
vodomira [7]

Answer:

y=\frac{-1}{2}x+1

Step-by-step explanation:

First, let's do the easiest part, finding the y-intercept, which shows up at the end of your slope intercept equation, y=mx+b, where slope is rise over run!

- Simply look for where the coordinate is on the y-intercept, which is at y = 1!

Then, we need to find our rise over run, which is basically counting from point a to point b. To get to the lower coordinate from the top, we go down two (-2), and over 4. Which means we "rose" -2, and "ran" 4! It's -2 because we went DOWN, and positive 4 because we went FORWARD. This gave us 2 over 4, which is the same as 1 over 2!

:D

3 0
3 years ago
Line a and b are perpendicular lines.If line a is represented by y=s/t x+10 and line b is represented by y=q/r -4 where s,t,q an
alekssr [168]

Answer:

The options are not shown, so i will answer in a general way.

First, for a line of the form:

y = a*x + b

All the perpendicular lines will have a slope of -(1/a), then we can write a general perpendicular line as:

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In this problem we have the perpendicular lines:

y=(s/t)*x+10

y = (q/r)*x - 4

Because those lines are perpendicular, we must have that:

(q/r) = -(1/(s/t)) = -(t/s)

q/r = -t/s

and we knew that s, t, q and r are integers (where t and r can not be equal to zero), and because of this relation, where we can see that in the denominator at the right we have the integer s, we can conclude that s can not be zero (we can not divide by zero).

And we know that t and s are both different than zero, then:

-t/s ≠ 0.

This means that:

q/r ≠ 0

And from this, we can conclude that q is different than zero.

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Abbigal will need to use three quarters of a cup mor of flour! Totallying one and a quarter cup of flour!
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