The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
c
Step-by-step explanation:
1/4 + 7/8 =
2/8 + 7/8 Convert the 1/4 to the denominator as 8 so we can add the top number.
9/8 Add the top number.
1 1/8 Simplifly the result.
Answer:
5n + 20
Step-by-step explanation:
Answer:
(16+25)×47
Step-by-step explanation:
..........
Answer:
LSA = 532 yds ^2
Step-by-step explanation:
We do not add the triangles in because they are the bases and the bases do not get added in the lateral surface areas.
From left to right
Rectangle 1
A = lw = 9.9 *20 =198
Rectangle 2
A = lw = 6.8 *20 =136
Rectangle 3
A = lw = 9.9 *20 =198
Add them together
198+136+198
532
LSA = 532 yds ^2
