Please help me on that, thank you.

Find the measure of ∠5.<br><br> Given:<br> ∠4 = 37°<br> ∠8 = 62°

Lisa [10]

Answer:

99

Step-by-step explanation:

Geometry is not my best subject but here's what I did:

The sum of the angles in a triangle is 180 so if we add 4 and 8 we can get angle 6

--> 180 - (37+62)

--> 180 - 99

---> 81

The sum of the angles on a line intersected at a point = 180

180 - 81 = Angle 5

Angle 5 = 99

5 0

4 years ago

Help plz! Evaluate the following definite integral:<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_%7B-a%7D%20%7B%28a%5E%7

s344n2d4d5 [400]

Just use the power rule:

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=a^2t-\dfrac13t^3\bigg|_{t=-a}^{t=a}$

We also could have use the fact that the integrand is even to write

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=2\int_{t=0}^{t=a}(a^2-t^2)\,\mathrm dt=2\left(a^2t-\dfrac13t^3\bigg|_{t=0}^{t=a}\right)$

I'll continue with this expression since it's easier to evaluate (if only a little):

$2a^3-\dfrac23a^3=\dfrac43a^3$

7 0

3 years ago

The sides of a square are three to the power of two sevenths inches long. What is the area of the square? (5 points) nine to the

kakasveta [241]

It's three to the power of four sevenths square inches.
Hope this will help you!

8 0

3 years ago

Read 2 more answers

If you were to make a quadrilateral by rotating triangle RST 180 about U which type of quadrilateral would form? A. Rectangle B.

crimeas [40]

Answer:

Rhombus

Step-by-step explanation:

A triangle when rotated around any point by 180° forms a Rhombus.

3 0

3 years ago

Read 2 more answers

find an equation of the line satisfying the given conditions. write the equation using function notation. Through (-20,5) and (-

denis23 [38]

Answer:

The equation of the line using function notation is

$y=f(x)=-\frac{1}{4}x$

Step-by-step explanation:

Given points are (-20,5) and (-36, 9)

Now to find the equation of the line passes through these points

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the two given points (-20,5) and (-36, 9) respectively.

To find slope

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{9-5}{-36-(-20)}$

$m=\frac{4}{-36+20}$

$m=\frac{4}{-16}$

$m=-\frac{1}{4}$

Therefore $m=-\frac{1}{4}$

The equation of the line is of thr form y=mx+c

The point (-20,5) passes through the above line and $m=-\frac{1}{4}$

$5=-\frac{1}{4}(-20)+c$

$5=5+c$

$c=0$

$y=-\frac{1}{4}x+0$

Therefore $y=-\frac{1}{4}x$

Therefore the equation of the line using function notation is

$y=f(x)=-\frac{1}{4}x$

6 0

3 years ago