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tiny-mole [99]
3 years ago
7

Help plz! Evaluate the following definite integral:

B2%7D%20-%20t%5E%7B2%7D%20%20%29%7D%20%5C%2C%20dt" id="TexFormula1" title="\int\limits^a_{-a} {(a^{2} - t^{2} )} \, dt" alt="\int\limits^a_{-a} {(a^{2} - t^{2} )} \, dt" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Just use the power rule:

\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=a^2t-\dfrac13t^3\bigg|_{t=-a}^{t=a}

We also could have use the fact that the integrand is even to write

\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=2\int_{t=0}^{t=a}(a^2-t^2)\,\mathrm dt=2\left(a^2t-\dfrac13t^3\bigg|_{t=0}^{t=a}\right)

I'll continue with this expression since it's easier to evaluate (if only a little):

2a^3-\dfrac23a^3=\dfrac43a^3

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Please help!!! keep in mind this is a REVIEW question. Which of the following is NOT a congruence transformation? A. a dilation
Lady_Fox [76]

Answer:

Hey there!

A congruence transformation maintains the size of the shape.

Thus, a dilation with scale factor 2 is not a congruence transformation.

Let me know if this helps :)

4 0
3 years ago
For each problem, explain or show your reasoning, a. 160 is what percentage of 40? b. 40 is 160% of what number? c. What number
grigory [225]

Answer:

A. 160 Out of 40 is 400%./// B. The answer is 25/// C.  The answer is 3905%

Step-by-step explanation:

( A )  One step solution:

You can easily find the answer in one step, just multiplying the part by 100 then dividing the result by the percentage.

So, 160 is 40% of =  <u>160 X 100   </u>   = 400

                                        40

                                             

( B ) The same thing as A but the numbers are switched

       One step solution:

You can easily find the answer in one step, just multiplying the part by 100 then dividing the result by the percentage.

So, 40 is 160% of = <u>40 × 100</u>      = 25

                                          160

( C ) Working out a percentage increase or decrease between two numbers is pretty simple. The resulting number (the second input) is 1602 and what we need to do first is subtract the old number, 40, from it:

1602 - 40 = 1562

Once we've done that we need to divide the result, 1562, by the original number, 40. We do this because we need to compare the difference between the new number and the original:

<u>1562  </u>    = 39.05          

40

We now have our answer in decimal format. How do we get this into percentage format? Multiply 39.05 by 100?

39.05 x 100 = 3905%

5 0
3 years ago
Please help asap!!!!
AlexFokin [52]

Answer:

3.14mm

Step-by-step explanation:

C = 2 pi r

3 0
3 years ago
The following equation has denominators that contain variables. For this equation write the value or values of the variable that
jarptica [38.1K]

Answer:

X = 3/5

Step-by-step explanation:

2/x=4/5x+2

Find the LCM of the denominator 5x and 1

2/x =4/5x + 2/1

2/x = (4 + 10x)/5x

Cross multiply the equation

2× 5x = (4+ 10x) × x

10x = 4x + 10x^2

Collect like term of the mixed number

10x - 4x = 10x^2

6x = 10x^2

Divide both side by 2x

6x/2x = {10x^2 } / 2x

3 = 5x

Divide both side by the coefficient of x

3/5 = 5x/5

X = 3/5

7 0
4 years ago
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
SCORPION-xisa [38]

Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

7 0
3 years ago
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