Is 6\{2}{7} irrational

A group of researchers wants to develop an experiment to determine whether a new drug effectively treats cancer. The researchers

yawa3891 [41]

Part A: The animals are used for examining and determining the effect of a particular new drug for the treatment of the diseases and disorders before they are examined over humans. This practice is called as clinical trial.

The ethical issue associated with given type of testing is that animals have right to live and survive. They should not be subjected to the treatment where they experience harm or even death.

Part B: Those assigned to the control take a sugar pill. The only thing you want to vary across groups when you're conducting an experiment is the treatment. Since taking pills is a part of taking medication (the treatment), medical experiments often employ something called a placebo-controlled study where outcomes for those who are randomly assigned to take the medication are compared to outcomes for those who are randomly assigned to take a sugar pill. The sugar pill is expected to have no effect, so it serves as a useful baseline to compare the treatment to.

Have a good day!!!! <3<3

8 0

3 years ago

The volume of a rectangular prism is b3 + 8b2 + 19b + 12 cubic units, and its height is b + 3 units. The area of the base of the

omeli [17]

Given:

The volume of the rectangular prism is

$b^{3}+8 b^{2} +19b+12$ ,

the height is h=(b+3)

1. The volume of a rectangular prism is (base area)*height

also, notice that the volume is a third degree polynomial, the height is a 1st degree polynomial, so the base area must be a 2nd degree polynomial, whose coefficients we don't know yet.
Let this quadratic polynomial be $(mb^{2}+nb+k)$

2

$b^{3}+8 b^{2} +19b+12=(mb^{2}+nb+k)*(b+3)$

notice that $b^{3}$ is the product of the largest 2 terms: $mb^{2}$ and b, so m must be 1

also, notice that 12 is the product of the constants, k and 3

so k*3=12, this means k=4

3
we write the above equality again:

$b^{3}+8 b^{2} +19b+12=(b^{2}+nb+4)*(b+3)$

$(b^{2}+nb+4)(b+3)= b^{3}+3 b^{2} +nb^{2}+3nb+4b+12$

= $= b^{3}+(n+3)b^{2}+(3n+4)b+12$

4
now compare the coefficient with the left side:

$8 b^{2}=(n+3)b^{2}$

8=n+3

n=5

substituting n=5:

the base area is $b^{2}+5b+4$

Answer: $b^{2}+5b+4$

3 0

3 years ago

The sale price for a bicycle is $315 dollars. The original price was first discounted by 50% and then discounted an additional 1

Len [333]

This means that the bicycle was discounted in total by 60%, so $315 is 40% of the original price to get 40% to 100% youd multiply it by 2.5 so so the same to the price 315 x 2.5= 787.5

3 0

4 years ago

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Explain how you know that √10 is between 3 and 4? what would your estimate of √10 be??

raketka [301]

Answer:

Step-by-step explanation:

Welllllll.....

If you take the square root of 9, it's 3

if you take the square root if 16, it's 4

I would guess it to be about 3.2

4 0

3 years ago

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A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$

⇒ $probability = \frac{(17)}{52}$

⇒ $probability =0.3269$

Therefore, probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

8 0

3 years ago

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