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olganol [36]
3 years ago
6

Josue has to solve the equation -4x+8=2x+10.He notices he can first divide every term by factor of 2 to make the equation easier

to solve.Using Josue's strategy, which equation will result ?
Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

Step-by-step explanation:

-4x+8=2x+10

8=6x+10

-2=6x

x=-1/3

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A square picture with sides of 32 inches is to be mounted on a square mat with sides of 52 inches. Find the area of the mat that
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52^2 - 32^2 = 1680 inches²

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Jeremiah has a previous balance of $594 on a credit card with a 12.7% APR compounded monthly. If he made a payment of $25 this m
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A soup can has a diameter of 8 centimeters and a height of 15 centimeters how much soup does the can hold?
Ivan

Answer:

V = 240 pi

Step-by-step explanation:

We want the volume of a cylinder

V = pi r^2 h

We have the diameter and want the radius

r = d/2 = 8/2 = 4

V = pi ( 4)^2 * 15

V = pi * 16* 15

V = 240 pi

Let pi = 3.14

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8 0
3 years ago
Read 2 more answers
Plese help me its timed
Nadusha1986 [10]

Answer:

(3,2) I think

Step-by-step explanation:

X= 3

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3 0
2 years ago
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
3 years ago
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