Answer:
T=45m+23
Step-by-step explanation:
Answer:
625
Step-by-step explanation:
t= d/s
2500/4
I believe it would be negative 9 because your subtracting by twelve again. I hope that helped
Answer:
Charlie is incoerre
Step-by-step explanation:
Given that :
Line of sight to top of flagpole = 16 feets
Angle of elevation = 60°
The height of the flagpole :
Applying trigonometry to the drawing in the attached picture :
We use:
Sinα = opposite / hypotenus
This enables us to use the value of the hypotenus (line of sight) to obtain the missing height value (h)
Sin(60°) = h / 16
h = 16 * sin 60
h = 16 * 0.8660254
h = 13.856406
Hence flagpole is about 13.86 feets high
Charlie's reasoning is incorrect, the line of sight constitutes the hypotenus and not Adjacent and hence, shoul
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2