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Kazeer [188]
2 years ago
12

G=x-c/x. for xhow do yoy make this an equation for x? help

Mathematics
1 answer:
zzz [600]2 years ago
7 0
1.
\displaystyle \text{if }\quad G=x-  \frac{C}{x} \\\\

x \neq 0

Multiply both sides by x:

\displaystyle Gx=x\bigg(x- \frac{C}{x}\bigg )\\\\Gx=x^2-C

Subtract from both sides Gx:
Gx-Gx=x^2-C-Gx\\x^2-Gx-C=0

Then solve this equation:

\displaystyle x^2-Gx-C=0\\\\x_{1,2}= \frac{G\pm  \sqrt{G^2+4C} }{2}

2.
\displaystyle\text{if}\quad G= \frac{x-C}{x}

x \neq 0

Multiply both sides by x:

Gx=x-C

Subtract from both sides Gx:

x-C-Gx=0

Then solve this equation:

\displaystyle x-Gx-C=0\\x(1-G)=C\\x= \frac{C}{1-G}




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Solution:

<u>Note that:</u>

  • Abby's dog: 1.5 cups of food
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Looking at the information we got, we can say that Braxton's dog eats more. Let's put them into ratio form (Braxton's dog:Abby's dog)

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<u>Now, put them into fractions.</u>

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We can conclude that Braxton's dog eats 3 times more food.

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8. F

Step-by-step explanation:

7. Jorge leaves 2 hours early, and is going 20 miles per hour. So before Marcos starts going, Jorge has gone 40 miles (2*20). Then, 1 hour later, Jorge is at 60 miles and Marcos is at 40 (because he goes 40 miles per hour in his car). Another hour later, Jorge is at 80 (60+20) and Marcos is at 80 as well (40 + 40). They will both have gone 80 miles when Marcus catches up.

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