300 - 297 = 3
294 - 291 = 3
288 - 285 = 3
So, that is a sequence of sums of number 3: 3 + 3 + 3 + .... + 3
How may times will the number 3 be added?
Note that 300 is reduced in 6 units each time => 300 / 6 = 50 => 3 will be added 50 times.
=> 50 * 3 = 150
Answer: 150
The profit on each book is $ 5.25
<em><u>Solution:</u></em>
Given that, the drama club at school sells $ 15.00 coupon books
Their profit is 35% of the total sales
Therefore,
Cost of a coupon book = $ 15
Profit = 35% of the total sales
We have to find the profit on each book
If a book is sold for $ 15 and then profit will be 35 % of 15
Let us find 35 % of 15
Thus profit on each book is $ 5.25
Answer:
10.29 square meters
Step-by-step explanation:
Size of square:
2 x 2 = 4
Size of each semi-circle:
because there are 2 semi-circle we can count them as one circle
the circle has a diameter of 2
the circle has a radius of 1
circle equation:
area=2(22/7)(1)^2=6.29
6.29+4=10.29
Answer:
A. x = 1/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
- Standard Form: ax² + bx + c = 0
- Solving quadratics
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
4x² + 3 = 4x + 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Rewrite in standard form: 4x² - 4x + 1 = 0
- Factor: (2x - 1)² = 0
- Solve: x = 1/2
Peter borrows 226,950*0.9=204255
Assuming the mortgage is compounded monthly, the total monthly mortgage payment is
A=P(i(1+i)^n)/((1+i)^n-1)
where
A=monthly payment
P=amount borrowed (present value)=204255
i=monthly interest = 0.0625/12
n=number of months = 30*12=360
A=monthly payment
=P(i(1+i)^n)/((1+i)^n-1)
=204255(.0625/12(1+.0625/12)^360)/((1+.0625)^360-1)
=1257.63
His monthly payment
=10% of income
=10% of $2985
=298.50
So minimum rent = 1257.63-298.50 = $959.13
