First you subtract the two equations
x^2-2x+3-6x
You simplify that and get
x^2+4x+3 = 0
Now we solve using the quadratic formula.
We get x = -1 and x = -3.
Now we find the y values by plugging the x values into the equation.
f(x) is the same as y.
y = (-1)^2 - 2(-1) + 3
y = 1+2+3
y = 6
Now for the other x value.
y = (-3)^2 - 2(-3) + 3
y = 9+9
y = 18
So the two ordered pairs are (-1,6) and (-3,18)
3/4 and 1/3
4x3 = 12 that will be the common denominator.
For 3/4 we first divide 12/4 = 3 and then multiply 3 x3 = 9 that's the numerator
For 1/3 we first divide 12/3 = 4 and then multiply 1x4 = 4 that's the numerator
The fractions will be rewrited as: 9/12 and 4/12
The answer to your question is 3k^2m^6/4
