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2 years ago

PLEASE HELP I DONT KNOW HOW TO DO IT PLEASEEEE

Mathematics

2 answers:

dmitriy555 [2]2 years ago

8 0

t( 15 ) = t( 1 ) + [ 14 × ( Constant value ) ]

________________________________

t( 1 ) = 1

Constant value = t( 2 ) - t( 1 ) = t( 3 ) - t( 2 )

Constant value = 6 - 1

Constant value = 5

________________________________

Thus :

t ( 15 ) = 1 + [ 14 × 5 ]

t( 15 ) = 1 + 70

t( 15 ) = 71

denis-greek [22]2 years ago

6 0

Answer:

Step-by-step explanation:

so the sequence(pattern) is it increases by 5

there are 2 ways to solve this promblem

one count on your toes and hands by 5 starting at one until u get to 10 fingers and 5 toes. soon the promblems will get harder and you cant do that

other way multiply 5 by 15 and add it to 1

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What is the cost of one cranberry and one banana nut muffin?

Bezzdna [24]

So for the cranberry muffin, for every 12 (a dozen) it's $3
Banana nut muffin: for every 12, it's $4.32
take the $3 and divide it by 12 which is $0.25 for every cranberry muffin
take $4.32 divide by 12 and you get $0.36 for every banana nut muffin
so $0.25 + $0.36 = $0.61
Therefore the answer is B

8 0

2 years ago

Read 2 more answers

Part of arianna’s earnings are based on a 5% commission rate. At the end of the day arianna earned 14.98 in commission. How much

Katarina [22]

Arianna sold for $ 299.6

Solution:

Given that, Part of Arianna’s earnings are based on a 5% commission rate

At the end of the day arianna earned 14.98 in commission

Therefore,

Commission earned = $ 14.98

Commission rate = 5 %

Let "x" be the amount that Arianna sell that day

Therefore, according to question,

5 % of amount earned = 14.98

5 % of "x" = 14.98

Solve the above equation for "x"

$5 \% \times x = 14.98\\\\\frac{5}{100} \times x = 14.98\\\\5x = 14.98 \times 100\\\\5x = 1498\\\\Divide\ both\ sides\ of\ equation\ by\ 5\\\\x = 299.6$

Thus arianna sold for $ 299.6

7 0

3 years ago

Let F of x equals the integral from 1 to 3 times x of the natural logarithm of t squared. Use your calculator to find F″(1).

eduard

Reading that as

$F(x)=\displaystyle\int_1^{3x}(\ln t)^2\,\mathrm dt$

By the fundamental theorem of calculus, the first derivative is

$F'(x)=3(\ln(3x))^2$

and so the second derivative would be

$F''(x)=\dfrac{6\ln(3x)}x$

which means

$F''(1)=6\ln3$