Answer:
t=1.283 seconds and
0.779 seconds
Step by step Explanation:
Given: h=18 ft
The given equation is h=2+33t-16t²
Then if we substitute the value of given h, h=18 ft into the given equation we have,
18=2+33t-16t²
Then if we re- arrange we have
16t²−33t+16=0
We can see that the above quadratic equation is in standard form, with a=16, b=33 and c=16 then we can use quadratic formula in solving it which is
t= −(−33±√[(−33) ²−4×16×16)]/(2×16)
= [33±√[1089−1024]/(32)
= [33±√[65]/(32)
=1.283 or 0.779 seconds
the two real roots , of the quadratic are:
1.283 and
0.779 seconds
t= 1.283 or 0.779 seconds
Hence, the ball is at 18 feet with height 0.779seconds after it has been thrown up and,
and is at 21 feet with height 1.283 seconds after after thrown down
I will assume you meant D(x)=23(1.0032)^x, if so:
The growth rate as a percentage is 100(.0032)=0.32% (about 1/3 of 1%)
Given:
h = melting point of helium
j = melting point of hydrogen
k = melting point of neon
Number of values = 3
Therefore, the average is
(Sum of values)/(Number of values) = (h+j+k)/3
Answer:
The average melting point of helium, hydrogen, and neon is
(h+j+k)/3
It is divisible by the numbers: 1,2,3,4,5,6,7, and 9
Step-by-step explanation:
yes just divide it by 5 and you'll get the answer
