Answer:
The objective function is to minimize cost thru use of linear programming
Explanation:
A craftsman named William Barnes builds two kinds of birdhouses, one for wrens and a second for bluebirds. Each wren birdhouse takes 4 hours of labor and 4 units of lumber. Each bluebird house requires 2 hours of labor and 12 units of lumber. The craftsman has available 72 hours of labor and 120 units of lumber. Wren houses yield a profit of $ 10 each and bluebird houses yield a profit of $ 15 each. The aim of the objective function for William should be to ▼ Minimize Maximize the objective value.
The objective function is to minimize cost thru use of linear programming
Answer:
Anne Mullens committed embezzlement.
Explanation:
Embezzlement is defined as misappropriation of funds by someone with whom funds have been entrusted.
It is a theft as the money does not belong to the perpetrator. The perpetrator is only entrusted with funds.
One of the conditions for embezzlement is an existence of a fiduciary (trust) relationship between parties.
In the given case, Anne Mullens pocketed $57 cash from recorded amount instead of recording 57$ customer's payment via check. Instead she included the customer's check in the money to be taken to bank.
This is embezzlement of funds by Anne.
Answer:
28%
Explanation:
She is an RHIA, which requires 30 hours of continuing education every two-year cycle.
Hence, 8.5/30 = 28.3 =28%( to the nearest whole number).
Asset S has a greater Straight Line Depreciation.
Explanation:
Straight Line Depreciation amount = (Capitalised Cost - Salvage Value) / Life of the asset
Capitalised Cost = Purchase cost + Installation cost
For Asset L,
- Capitalised Cost = $4,000,000.00 + $750,000.00
- Capitalised Cost = $4,750,000.00
Asset Life = 15 years
Salvage/residual value = $0.00
So,
Straight Line Depreciation of Asset L
- Depreciation Amount = $4,750,000 / 15
- Depreciation Amount = $316,666.67
So, Depreciation Amount for Asset L is $316,666.67
For Asset S,
- Capitalised cost = $2,000,000.00 + $500,000.00
- Capitalised cost = $2,500,000.00
Asset Life = 5 years
Salvage/Residual Value = $400,000.00
So,
Straight Line Depreciation of Asset S
- Depreciation Amount = ($2,500,000 - $400,000) / 5
- Depreciation Amount = $420,000.00
So, Depreciation Amount for Asset S is $420,000.00
So, Asset S has a greater Straight Line Depreciation.
This is a. ir reaction strategies by defitnition.