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frosja888 [35]
2 years ago
14

A spinner has 8 equal sectors labeled from 1 to 8. The spinner is spun twice.

Mathematics
2 answers:
FromTheMoon [43]2 years ago
5 0
The answer would be 1/4
muminat2 years ago
4 0
On your first spin the chance is 1/2. The same goes for your second spin, but the chance of getting two consecutive even numbers is 1/2 x 1/2.
So the answer is 1/4.
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A machinist is allowed 1% tolerance on a shaft that measures 15 inches long. What is the amount of tolerance
Sauron [17]
Tolerance = 1% = 0.01 on a shaft of 15 in
Tolerance in inches = 15 x 0.01 =0.15 in
Since it' s a tolerance the acceptable error is either +0.15in or -0.15 in

8 0
2 years ago
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A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud
8_murik_8 [283]

Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

\bar x = 7.10 -- sample mean

\sigma=5 --- sample standard deviation

n = 150 --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

CI = 90\% --- the confidence interval

Calculate the \alpha level

\alpha = 1 - CI

\alpha = 1 - 90\%

\alpha = 1 - 0.90

\alpha = 0.10

Divide by 2

\frac{\alpha}{2} = 0.10/2

\frac{\alpha}{2} = 0.05

Subtract from 1

1 - \frac{\alpha}{2} = 1 - 0.05

1 - \frac{\alpha}{2} = 0.95

From the z table. the critical value for 1 - \frac{\alpha}{2} = 0.95 is:

z = 1.960

Solving (c): Margin of error

This is calculated as:

E = z * \frac{\sigma}{\sqrt n}

E = 1.960 * \frac{5}{\sqrt {150}}

E = 1.960 * \frac{5}{12.25}

E =  \frac{1.960 *5}{12.25}

E =  \frac{9.80}{12.25}

E =  0.800

Solving (d): The confidence interval

This is calculated as:

CI = (\bar x - E, \bar x + E)

CI = (7.10 - 0.800, 7.10 + 0.800)

CI = (6.3, 7.9)

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0
2 years ago
Ahhh I’m stuck on this one please help
vodomira [7]

Answer:

1.20 ÷ 4 = 0.30 per unit

Please mark as brainliest;)

8 0
2 years ago
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I need help Asap!!!!!!!!!
kobusy [5.1K]
-8 and 3 ...... I think
6 0
3 years ago
Kirsten walked 230 meters in 50 seconds. What was Kirsten's speed?
choli [55]
4.6 meters per second was her walking speed
3 0
3 years ago
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