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a_sh-v [17]
3 years ago
5

"According to contractarian logic, we should be willing to make concessions to others if they agree to make comparable and recip

rocal concessions, with the overall result being that everyone gets a desired benefit with an acceptable minimum of sacrifice on each side. Please identify, and briefly analyze, a situation or scenario that illustrates this principle. "
Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:In a couple with a newborn baby at home, to take turns on feeding the baby at night.

Step-by-step explanation: Here both parents are willing to sacrifice a few minutes, if not hours of sleeptime with the promise to be allowed to rest the next time the baby needs to be fed. There is no certainty in how long it will take for the baby to go back to sleep or how long it will be for the baby to be awake again, but the chances are the same for both parents, so they both agree to take care of the child one at a time with the promise to be in turns, this is an example of contractarian logic.

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Natasha, Peter and Malachy share ?56 in a ratio 1:1:2. How much money does each person get? Natasha: ?? Peter: ?? Malachy: ??
Ahat [919]

Answer:

Natasha = 1 x 14 = 14

Peter = 2 x 14 = 28

Malachy = 1 x 14 = 14

Step-by-step explanation:

Ratio 1:1:2 so 1 + 1 + 2 = 4

Natasha, Peter and Malachy share of 56 : 56/4 = 14

Natasha = 1 x 14 = 14

Peter = 2 x 14 = 28

Malachy = 1 x 14 = 14

3 0
3 years ago
4. The vertices of a triangle are A(-3, 1), B(-3, 4), and C(1, 2). After translation, A' is the point (-1, -4). Find the transla
diamong [38]
A(-3, 1) to <span>A' is the point (-1, -4)
rule
</span><span>(x, y) --> (x + 2, y - 5); B' (-1, -1)</span>
3 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
Can someone please help me​
castortr0y [4]

Answer:

2x3 +10x2 -2x -10

Step-by-step explanation:

x2 + x + 5x + 5

(x2 + 6x + 5 )(2x -2)

2x3 + 12x2 + 10x - 2x2 -12x - 10

2x3 +10x2 -2x -10

4 0
3 years ago
Read 2 more answers
Please help! I am stuck!
Mrac [35]

the answer is D the last one,

the reason is just that any negative number is automatically smaller than a positive number. so -2.8 is smaller than even the smallest decimal possible as long as that decimal is positive. 1.4 is actually about 3 time more that -2.8

(both are still freezing cold)

5 0
3 years ago
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