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tatuchka [14]
3 years ago
6

Find the area of this figure

Mathematics
1 answer:
kherson [118]3 years ago
8 0

Answer:

45cm

Step-by-step explanation:

3 x 5 x 3 x 1/2

(if im wrong im sorry)

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Convert the rational number below to a decimal. Round to the nearest hundredth when necessary. 3/5
Gekata [30.6K]

Answer:  0.6

Explanation:   You need to divide 3 by 5 and it will give you the answer of 0.6

5 0
2 years ago
Asibi makes face covers. A customer has ordered five face covers. Asibi has 3/4 yard of fabric and each face cover requires 1/6
Volgvan

Answer:

1/12 yards

Step-by-step explanation:

5×1/6 yards = 5/6 yards

5/6 yards - 3/4 yards = 10/12 yards - 9/12 yards

= 1/12 yards

3 0
3 years ago
14+y = 3y+2, Find y with a step-by-step explanation.
mrs_skeptik [129]

Answer:

y= 6

Step-by-step explanation:

1. Rearrange the terms before the equal sign: 14+y=3y+2-> y+14=3y+2

2. Subtract 14 from both sides: y+14=3y+2-> y=3y-12

                                                     -14       -14

3. Subtract 3y from both sides: y=3y-12-> y-3y= -12

                                                -3y  -3y  

4. Combine like terms: y-3y= -12-> -2y= -12

                                      1-3 keep the y

5. Divide both sides by -2: -2y= -12-> y= 6

                                              /2    /2

6. So, you're left with y= 6

6 0
2 years ago
9x+12x-21=27<br> How do I solve ?
alexandr402 [8]
You gotta combine like terms which would be 9x and 12x which gives you 21x .

6 0
3 years ago
A carnival charges two different prices for admissions. Adults cost $4 while children cost $1.50. If a total of $5050 was collec
GenaCL600 [577]

Answer:

Step-by-step explanation:

We have to have 2 different equations to solve this.  One equation will represent the number of tickets sold while the other represents the money collected when the tickets were sold.

We know that adult tickets + children tickets = 2200 tickets.

That's the "number of tickets" equation.  Let's call adult tickets "a" and children's tickets "c".  So a + c = 2200

Now if each adult costs $4, then the expression that represents that as a cost is 4a.  If there is 1 adult, the cost is $4(1) = $4; if there are 2 adults, the cost is $4(2) = $8; if there are 3 adults, the cost is $4(3) = $12, etc.

The same goes for the children's tickets.  If each child's ticket is $1.50, then the expression that represents the cost of a child's ticket is 1.5c (we don't need the 0 at the end; it doesn't change anything to drop it off).  The total money brought in from the cost of these tickets was $5050, so

4a + 1.5c = 5050

Let's solve the first equation for a.  If a + c = 2200, then a = 2200 - c.  Sub that into the second equation and solve it for c:

4(2200 - c) + 1.5c = 5050 and

8800 - 4c + 1.5c = 5050 and

-2.5c = -3750 so

c = 1500

That means that there were 1500 children's tickets sold.  If a + c = 2200, then a + 1500 = 2200 so

a = 2200 - 1500 so

a = 700

There were 1500 children's tickets sold and 700 adult tickets sold.

7 0
3 years ago
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