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never [62]
3 years ago
12

point P is located at (-2, 7), and point R is located at (1, 0). find the y value for the point Q that is located 2/3 the distan

ce from point P to point R
Mathematics
1 answer:
natulia [17]3 years ago
7 0

Answer: 7/3


Step-by-step explanation:

R-P= (3,-7). the displacement vector.

P+x(R-P) moves to x times distance between

P+(R-P) = R moves to 100% of the distance.

Q = P+2/3(R-P)

= (-2,7)+2/3(3,-7)

= (-2,7)+(2,-14/3)

= (0,7-14/3)

= (0,7/3)

= (0,2.3333...)

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Solve 11 ≤ w + 3.4 i dont know the answer please help me
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Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

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6 0
2 years ago
Peter drove 432 Mi over a period of 6 hours while his best friend Eric drove 360 miles over 5 hours who had the faster unit righ
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Answer:

Both Peter and Eric had the same unit rate of 72mph.

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3 years ago
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2 years ago
100 PTS!! PLEASE HELP! OVER DUE
Reika [66]

Answer:

-\frac{1}{2} \vec {c}

Step-by-step explanation:

Look at the component form of each vector.

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If one imagined the line that contained each vector, the line for both would have a slope of 1, because \frac{4}{4}=1=\frac{-2}{-2}

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector.  This means that there is some number "k", such that k \vec{c} = \vec {d}, or equivalently, kc_x=d_x and kc_y=d_y.

If kc_x=d_x and kc_y=d_y, we just need to substitute known values and solve for k:

kc_x=d_x\\k(4)=(-2)\\k=\dfrac{-2}{4}\\k=-\frac{1}{2}

Double checking that k works for the y-coordinates as well:

kc_y=d_y

(-\frac{1}{2}) (4)    ?    (-2)

-2=-2 \text{ } \checkmark

So, -\frac{1}{2} \vec {c} = \vec {d}

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2 years ago
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