Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed
Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.
Car B traveled at 60 miles per hour.
Answer:
7g+14h
Step-by-step explanation:
hope it helped you
Answer:
B) A/l
Step-by-step explanation:
Isolate the variable, w. Note the equal sign, what you do to one side, you do to the other.
Divide l from both sides of the equation:
A = l * w
(A)/l = (l)/l * w
w = A/l
B) A/l is your answer.
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<em>4x-79=3x-29</em>
<em>Move the terms with "x" on the left, and the numbers on the right.</em>
<em>4x-3x=79-29</em>
<em>x=50</em>
