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3 years ago

How do you write mixed numbers or fractions as decimals?

1 answer:

7 0

To write fractions as decimals divide the numerator by the denominator, for example 3/4 3 divided by 4 equals 0.75 so 3/4 as a decimal is 0.75. If you want to do that with a mixed number, 3 3/4 3 divided by 4 equals 0.75 then add the 3 so 3 3/4 is equal to 3.75.

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The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term

rjkz [21]

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

= 3(x² - 4x + 4) + 4

= 3x² - 12x + 12 + 4

= 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

5 0

3 years ago

Estimate 3/8 + 3/4 + 7/8 =

goldfiish [28.3K]

Answer:

Step-by-step explanation:

3/8+3/4+7/8

=3/8+6/8+7/8

=16/8

8 0

2 years ago

The total practice time for a football team is 4,380 hours. There are 73 players. How many hours does each player practice?

VikaD [51]

Each team-mate practices for 60 hours.

You know this because if you divide 4,380 (the total amount of hours) by 73 (the total amount of players) you get 60.

3 0

3 years ago

How to work it out logically? Question a !!!

Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

$=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha$

Area of region 2 = ar(DHBC)

$=2000\times1500\\\\=3000000m^2=300ha$

Area of region 3 = ar(GFEH)

$(2000+1500)\times 1000\\\\=3500000m^2=350ha$

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

=987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ $ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m$