How do you write mixed numbers or fractions as decimals?

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

Plzzzz helppppppppppppppp

GarryVolchara [31]

Answer:

ok

Step-by-step explanation:

5 0

3 years ago

Which of the following functions is graphed below?

svetoff [14.1K]

<h3>Answer:</h3>

C (see attached)

<h3>Step-by-step explanation:</h3>

The linear portion of the graph is defined for x ≥ 1, with the point x=1 included. Only selections A and C do that.

The quadratic portion of the graph is defined for x < 1. Only selection C does that. (Selection A is doubly-defined for x > 1, so is not a function. It is undefined for x < 1.)

5 0

3 years ago

Complete the table for the given rule. Rule: y=x-1/4

mash [69]

Answer:

i don't see the question, but i can help you

Step-by-step explanation:

8 0

3 years ago

How do I solve this????

Arlecino [84]

Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater

so "b" is "4 more than 5 times" "a"

so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4

so.. whatever "a" is, "b" is 5a+4

now, their sum is 22, as opposed to "zz" hehe

so $\bf \begin{cases}
a+b=22\\
--------------\\
\boxed{b}=5a+4\qquad thus\\
--------------\\
a+\boxed{5a+4}=22
\end{cases}$

solve for "a", to see what the smaller one is

what's "b"? well, b = 5a + 4

3 0

3 years ago