A bag contains 7 marbles: one each of red, orange, yellow, green, blue, violet, and white. a child randomly pulls 4 marbles from
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Answer:
The price of each hamburger is $3
The price of each hot dogs is $2 .
Step-by-step explanation:
Given as :
The total price of 3 hamburger and 2 hot dogs = $13
The total price of 2 hamburger and 5 hot dogs = $16
Let The price of each hamburger = $x
Let The price of each hot dogs = $y
<u>Now, According to question</u>
3 x + 2 y = 13 .........A
2 x + 5 y = 16 .......B
Now, Solving to eq A and B
3 × (2 x + 5 y ) - 2 × (3 x + 2 y ) = 3 × 16 - 2 × 13
Or, (6 x + 15 y) - (6 x + 4 y) = 48 - 26
Or, (6 x - 6 x) + (15 y - 4 y) = 22
Or, 0 + 11 y = 22
∴ y =
i.e y = $2
so, The price of each hot dogs = y = $2
<u>Now, Put the value of y into eq B</u>
i.e 2 x + 5 y = 16
or, 2 x + 5 × 2 = 16
or, 2 x = 16 - 10
or, 2 x = 6
∴ x =
i.e x = $3
So, The price of each hamburger = x = $3
Hence, The price of each hamburger is $3 and The price of each hot dogs is $2 . Answer
A) For f(-1) we use the part of the piecewise function for when x < 0 because -1 < 0. Plug in -1 for x:
2(-1) + 3 = 1
b) For f(0), we use the part for when x
0.
4(0) + 5 = 5
c) For f(2) we use the part for when x 0.
4(2) + 5 = 13
2(-1) + 3 = 1
b) For f(0), we use the part for when x
4(0) + 5 = 5
c) For f(2) we use the part for when x
4(2) + 5 = 13